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Moment of Inertia Converter

Convert between kg·m², g·cm², slug·ft², lb·ft², and other moment of inertia units.

Moment of Inertia Converter

Enter a moment of inertia and select its unit — all other units update instantly.

Why Mass Farther From the Axis Matters More — I = Σmr²

ROTATION AXISmmm0.5rr2r

Same mass m at different distances — all rotate together

Each particle's contribution to I:

0.25 mr²(0.5r)² = 0.251 mr²(r)² = 14 mr²(2r)² = 4 — 4× the contribution!

Total I = 0.25mr² + 1mr² + 4mr² = 5.25 mr² — the particle at 2r alone contributes 76% of the total.

Common Moment of Inertia Values

How to Convert Between Kg·m², Lb·Ft², and G·cm²

Your flywheel design specifies I = 0.35 kg·m². Your US supplier quotes in lb·ft². Type 0.35, select kg·m², and see that it equals 8.31 lb·ft², 3,500,000 g·cm², and 120.4 lb·in². The interactive visualisation shows how mass distribution affects the result.

The converter handles 9 units: kg·m², g·cm², kg·cm², slug·ft², slug·in², lb·ft², lb·in², oz·in², and oz·ft². A physics student measuring a lab disk at 2,500 g·cm² sees it equals 0.00025 kg·m² and 0.00828 lb·ft². An aerospace engineer working with a satellite at 50 kg·m² sees it equals 3.74 slug·ft². The interactive demo shows three equal masses at distances r, 2r, and 3r contributing I, 4I, and 9I.

Why distance matters more than mass for flywheels

Flywheels store energy proportional to I

A flywheel stores rotational energy as E = 0.5 x I x ω². Doubling the moment of inertia doubles the stored energy. But I depends on mass distribution: a flywheel with mass at the rim has 2x the I of a solid disk of the same mass. This is why flywheels are designed with thick rims: maximum I for minimum mass.

Figure skater pulls arms in to spin faster

A skater spinning at 3 rev/s with arms extended (I = 4.0 kg·m²) pulls arms in and I drops to 1.0 kg·m². Angular momentum L = Iω is conserved, so ω increases from 3 to 12 rev/s. The skater spins 4x faster by reducing I to 1/4. This demonstrates the I = mr² relationship: halving the radius quarters the moment of inertia.

Car engine crankshaft must balance I across cylinders

A 4-cylinder engine has a crankshaft with I = 0.02 kg·m². Each piston contributes differently depending on its position in the firing order. The crankshaft must be balanced so that the total I is uniform through the rotation cycle. Uneven I causes vibration. Converting between lb·in² (US machining) and kg·m² (SI simulation) ensures the balance is correct.

How the Moment of Inertia Converter Handles Kg·m² and Lb·Ft²

All conversions pass through kilogram-meters squared (kg·m²). When you enter 0.35 kg·m² (a car flywheel), the tool divides by each target unit's factor: by 0.042140 for lb·ft², by 10^7 for g·cm², by 0.002926 for lb·in². The result: 0.35 kg·m² = 8.31 lb·ft² = 3,500,000 g·cm² = 120.4 lb·in².

Why g·cm² is 10 million times smaller than kg·m²

1 g·cm² = (0.001 kg) x (0.01 m)² = 0.001 x 0.0001 = 10^-7 kg·m². The centi prefix (10^-2) is squared for the distance term, and the kilo-to-gram conversion (10^-3) applies to mass. So 1 g·cm² = 10^-7 kg·m², meaning kg·m² is 10 million times larger. This is why lab apparatus outputs in g·cm² look like huge numbers (2,500,000) while the same object in kg·m² is tiny (0.25).

Shape formulas and how mass distribution affects I

Solid disk: I = 0.5 x m x r². Thin hoop: I = m x r² (twice the disk because all mass is at the rim). Solid sphere: I = 0.4 x m x r². Thin rod about centre: I = (1/12) x m x L². For a 2 kg disk at 0.1 m radius: I = 0.5 x 2 x 0.01 = 0.01 kg·m². For a 2 kg hoop at the same radius: I = 2 x 0.01 = 0.02 kg·m². The hoop has 2x the I of the disk.

The parallel axis theorem (I = I_cm + m x d²) lets you calculate I about any axis if you know I about the centre of mass. For a disk of I_cm = 0.01 kg·m² and mass 2 kg, shifted 0.05 m from centre: I = 0.01 + 2 x 0.0025 = 0.015 kg·m². This is widely used in engineering for compound shapes and assemblies.

Frequently Asked Questions

How do I convert 0.35 kg·m² to lb·ft²?

Divide by 0.042140: 0.35 / 0.042140 = 8.31 lb·ft². This is a typical car flywheel moment of inertia. For a quick estimate, multiply kg·m² by 23.73 to get lb·ft² (since 1/0.042140 = 23.73). The converter shows all units simultaneously so you can verify the relationships.

What affects moment of inertia more, mass or distance?

Distance, because I depends on r². Doubling the distance from the axis quadruples I. Doubling the mass only doubles I. A 1 kg mass at 2 m radius has I = 4 kg·m². A 4 kg mass at 1 m radius has I = 4 kg·m². Same I, but the 4 kg mass has 4x the weight. This is why flywheels put mass at the rim.

What is the moment of inertia of a solid disk vs a hoop?

Solid disk: I = 0.5 x m x r². Thin hoop: I = m x r². For the same mass and radius, the hoop has twice the moment of inertia because all its mass is at the maximum distance from the axis. A 2 kg disk at 0.1 m: I = 0.01 kg·m². A 2 kg hoop at 0.1 m: I = 0.02 kg·m². The hoop stores twice the rotational energy at the same speed.

How does a figure skater spin faster by pulling arms in?

Angular momentum L = Iω is conserved. With arms extended, I = 4.0 kg·m² and ω = 3 rev/s. Pulling arms in reduces I to 1.0 kg·m². Since L is constant, ω must increase to 12 rev/s. The skater spins 4x faster by reducing I to 1/4. This demonstrates the I = mr² relationship.

What is the parallel axis theorem?

I = I_cm + m x d², where I_cm is the moment of inertia about the centre of mass, m is total mass, and d is the distance between axes. For a 2 kg disk with I_cm = 0.01 kg·m², shifted 0.05 m: I = 0.01 + 2 x 0.0025 = 0.015 kg·m². This theorem is essential for calculating I of complex assemblies and compound shapes.

What is the moment of inertia of Earth?

Earth has I = 8.04 x 10^37 kg·m². It is approximately a solid sphere with mass 5.97 x 10^24 kg and radius 6.371 x 10^6 m. I = 0.4 x m x r² = 0.4 x 5.97e24 x (6.371e6)^2 = 8.04e37 kg·m². Earth's rotation rate changes slightly due to tidal friction, which changes its moment of inertia by about 10^-8 per century.

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